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Genetic Analysis: An Integrated Approach, 3e (Sanders)
Chapter 2 Transmission Genetics
2.1 Multiple-Choice Questions
1) Genetic crosses in which F1 plants heterozygous for a given allele are crossed to generate a
3:1 phenotypic ratio in the F2 generation are known as ________.
A) replicate crosses
B) reciprocal crosses
C) test crosses
D) monohybrid crosses
E) dihybrid crosses
Answer: D
Section: 2.2
Skill: Remembering/Understanding
LO: S2.2a, S2.2b
2) In peas, the smooth allele is dominant over the wrinkled allele. A plant with round peas was
crossed to a plant with wrinkled peas and all of the resulting plants had smooth peas. What are
the genotypes of the parents in this cross?
A) RR ร rr
B) RR ร Rr
C) Rr ร rr
D) Rr ร Rr
E) rr ร rr
Answer: A
Section: 2.2
Skill: Applying/Analyzing
LO: S2.2c
3) In peas, the yellow allele is dominant over the green allele. A plant with yellow peas was
crossed to a plant with green peas. The resulting plants were 50% yellow and 50% green. What
are the genotypes of the parents in this cross?
A) YY ร yy
B) YY ร Yy
C) Yy ร yy
D) Yy ร Yy
E) yy ร yy
Answer: C
Section: 2.2
Skill: Applying/Analyzing
LO: S2.2c
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4) What genotypic ratio would you expect to observe among the progeny of a monohybrid cross?
A) 1:3
B) 9:3:3:1
C) 1:2:1
D) 1:3:2:1
E) 3:1
Answer: C
Section: 2.2
Skill: Applying/Analyzing
LO: S2.2b
5) You count 1000 F2 seeds from a monohybrid cross. How many seeds do you expect to display
the dominant phenotype?
A) 1000
B) 750
C) 500
D) 250
E) 0
Answer: B
Section: 2.2
Skill: Applying/Analyzing
LO: S2.2b
6) Assuming independent assortment, what phenotypic ratio would you expect to see if an
individual with the genotype RrGg is self-crossed?
A) 1:3
B) 9:3:3:1
C) 1:2:1
D) 1:3:2:1
E) 3:1
Answer: B
Section: 2.3
Skill: Applying/Analyzing
LO: S2.3a
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7) In peas, axial (A) flower position is dominant to terminal (a), tall (L) is dominant to short (l),
and yellow (Y) is dominant to green (y). If a plant that is heterozygous for all three traits is
allowed to self-fertilize, how many of the offspring would show the dominant phenotype for all
three traits?
A) 3/64
B) 9/64
C) 27/64
D) 32/64
E) 64/64
Answer: C
Section: 2.3
Skill: Applying/Analyzing
LO: S2.3d
8) In peas, axial (A) flower position is dominant to terminal (a), and tall (L) is dominant to short
(l). If a plant that is heterozygous for both traits is allowed to self-fertilize, how many of the
offspring would also be heterozygous for both traits?
A) 9/16
B) 1/4
C) 3/16
D) 1/8
E) 1/16
Answer: B
Section: 2.3
Skill: Applying/Analyzing
LO: S2.3b
9) What phenotypic ratio would you expect as a result of a test cross between two individuals
where one that is homozygous recessive for alleles at two independent loci?
A) 3:1
B) 1:2:1
C) 1:1:1:1
D) 9:3:3:1
E) 9:4:2:1
Answer: C
Section: 2.3
Skill: Applying/Analyzing
LO: S2.3a
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10) If a plant with purple, axial flowers and green, inflated pods is heterozygous for all four
genes, how many different types of gametes can it produce?
A) 1
B) 4
C) 8
D) 9
E) 16
Answer: E
Section: 2.3
Skill: Applying/Analyzing
LO: S2.3e
11) In Guinea pigs, short hair (S) is dominant over long hair (s), rough coat (R) is dominant over
smooth coat (r), and black hair (B) is dominant over white hair (b). Which of the following
individuals could produce these (and only these) four possible gametes: SRb, Srb, sRb, srb.
A) SSRRbb
B) ssRrBB
C) SsRrbb
D) SsRrBb
E) SSRrBb
Answer: C
Section: 2.3
Skill: Applying/Analyzing
LO: G3, S2.3e
12) The gene L determines hair length in rabbits. The gene B determines hair color. A rabbit
with long, black hair is crossed to a rabbit with short, white hair. All the offspring have long,
black hair. What are the genotypes of the parents?
A) LLBB ร llbb
B) LlBb ร LlBb
C) LlBb ร llbb
D) Llbb ร llBb
E) Impossible to determine from the information given
Answer: A
Section: 2.3
Skill: Applying/Analyzing
LO: S2.3d
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13) In rabbits, long hair and black fur are produced by the dominant alleles L and B, which assort
independently. The genotype ll produces short hair and the genotype bb produces white fur. A
cross between a male with short, black fur and a female with long, white fur produces four
offspring with short, black fur, four offspring with long, white fur, four offspring with short,
white fur, and four offspring with long, black fur. What are the genotypes of the parents?
A) llBB ร LLbb
B) LlBb ร LlBb
C) llBb ร Llbb
D) LLBB ร llbb
E) Impossible to determine from the information given.
Answer: C
Section: 2.3
Skill: Applying/Analyzing
LO: S2.3d
14) A couple has four children. What is the probability that they have four boys?
A) 1/2
B) 1/4
C) 1/8
D) 1/16
E) 1/32
Answer: D
Section: 2.4
Skill: Applying/Analyzing
LO: G4, S2.4
15) By convention, when an OBSERVED experimental outcome has a probability of occurrence
of less than 5% ( 0.05). Therefore, the chance hypothesis that the two genes assort
independently cannot be rejected.
Section: 2.5
Skill: Applying/Analyzing
LO: G2, G3, G4, G9, S2.3b, S2.3c, S2.5
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6) A geneticist is investigating the inheritance of two autosomal recessive genes in mice, one for
obesity (LEP) and another for autism (oprm1). The table below provides the number of offspring
observed, for each phenotype, when dihybrid mice are testcrossed:
Phenotype
Observed(O) Expected (E)
wild-type
88
obese
68
autistic
64
obese, autistic
80
O-E (O-E)2
(O-E)2/E
โ (O-E)2/E=
Fill in the table above and determine:
a. the chi-square (ฯยฒ) value (to the nearest hundredth) for the chance hypothesis that the two
genes assort independently
b. the degrees of freedom
c. whether or not you would reject your chance hypothesis that the two genes assort
independently, based on your approximate P value, and the justification for why
Answer:
Phenotype
Observed(O) Expected (E) O-E (O-E)2
(O-E)2/E
wild-type
88
75
13
169
2.533
obese
68
75
-7
49
0.653
autistic
64
75
-11
121
1.613
obese, autistic
80
75
5
25
0.333
โ (O-E)2/E=
4.85
a. 4.85
b. 3
c. You would fail to reject the chance hypothesis since the observed outcomes have a P value
greater than 5% (> 0.05). Therefore, the chance hypothesis that the two genes assort
independently cannot be rejected.
Section: 2.5
Skill: Applying/Analyzing
LO: G2, G3, G4, G9, S2.3a, S2.3c. S2.5
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7) Tim and Mary are planning to start a familiy. While neither of them have cystic fibrosis, a rare
autosomal recessive disease, they are concerned that their children could have the disease since
Tim’s father, John, AND Mary’s brother, Ralph both have the disease.
a. Draw a pedigree of the inheritance of the cystic fibrosis allele in this family.
b. On your pedigree, indicate any individuals that must be carriers.
c. What is the probability that Tim will be a carrier for the disease allele?
d. What is the probability that Mary will be a carrier for the disease allele?
e. What is the probability that Tim and Mary will have a child with the disease?
Answer:
a.
b.
c. 1
d. 2/3
e. 1/6
Section: 2.6
Skill: Evaluating/Creating
LO: G2, G3, G4, G5, S2.6b, S2.6c S2.6d
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